A definite mass of a monoatomic ideal gas at 1 bar and 27^{\circ} {C} expands against vacuum from 1.2 {dm}^{3} to 2.4 {dm}^{3}. The change in free energy of the gas, ∆ G, is ( {R}=0.80 bar - {L} \/ {K} -mol, \ln 2=0.7)

JEE Advanced 2020 Full Test 2 Paper 1

Question : 20 of 54

Marks: +1, -0

A definite mass of a monoatomic ideal gas at 1 bar and 27∘C expands against vacuum from 1.2 dm3 to 2.4dm3. The change in free energy of the gas, ∆G, is (R=0.80 bar −L∕K -mol, ln 2=0.7)

0
-64 bar -1
+84J
−84J

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