JEE Advanced 2020 Full Test 2 Paper 1

Question : 14 of 54

Marks: +1, -0

The distance between the parallel plates of a charged condenser is d=5cm and the intensity of the field E=300Vcm−1. A slab of dielectric constant K=5 and 1cm wide is inserted parallel to the plates. Determine the potential difference between the plates, after the slab is inserted. (in volt)