If \int_{0}^{\frac{\pi}{2}} \frac{d x}{a+b \cos x}= {1}/\sqrt{b^{2}-a^{2}}} \ln {b+\sqrt{b^{2}-a^{2}}}/{a}, (where b> a), then the value of \int_{0}^{\frac{\pi}{2}} \frac{\cos x}{(3+5 \cos x)^{2}} d x is

Correct Answer is : −116+564ln3

\frac{1}{16}+\frac{5}{64} \ln 3

\frac{1}{16}-\frac{5}{64} \ln 3

-\frac{1}{16}+\frac{5}{64} \ln 3

-\frac{1}{16}+\frac{64}{5} \ln 3

JEE Advanced 2020 Full Test 1 Paper 2

Question : 43 of 54

Marks: +1, -0

∫

‌

a+b‌cos‌x

=‌

√b2−a2

‌ln‌

b+√b2−a2

, (where b> a), then the value of

∫

‌

cos‌x

(3+5‌cos‌x)2

dx is

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