P(x)=x^{5}+x^{2}+1 \text{ has roots } x_{1}, x_{2}, x_{3}, x_{4}, x_{5} \text{ and } g(x)=x^{2}-2 \text{ then } g(x_{1}) \cdot g(x_{2}) \cdot g(x_{3}) \cdot g(x_{4}) \cdot g(x_{5})-30 g(x_{1} \cdot x_{2} \cdot x_{3} \cdot x_{4} \cdot x_{5})=4 x+3 \text{ then } {n} \text{ equal to }

JEE Advanced 2020 Full Test 1 Paper 1

Question : 52 of 54

Marks: +1, -0

P(x)=x5+x2+1‌ has roots ‌x1,x2,x3,x4,x5‌ and ‌g(x)=x2−2‌ then ‌
g(x1)⋅g(x2)⋅g(x3)⋅g(x4)⋅g(x5)−30g(x1⋅x2⋅x3⋅x4⋅x5)=4x+3
‌ then ‌n‌ equal to ‌

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