Given the equation of two circles as C_{1}: z \overline{z}+\overline{\alpha} z+\alpha \overline{z}+Y=0 and C_{2}: z \overline{z}+\overline{\beta} z+\beta \overline{z}+\delta=0 where \alpha, \beta \in C \& Y, \delta \in R

C_{1} \& C_{2} will touch externally if |\alpha-\beta|=\sqrt{|\alpha|^{2}-Y}+\sqrt{|\beta|^{2}-\delta}

C_{1} \& C_{2} will intersect orthogonally iff \alpha \overline{\beta}+\overline{\alpha} \beta=Y+\delta

Radius of circle {C}_{1} is \sqrt{|\alpha|^{2}-Y}

JEE Advanced 2020 Full Test 1 Paper 1

Question : 38 of 54

Marks: +1, -0

Given the equation of two circles as
C1:zz+αz+αz+Y=0 and C2:zz+βz+βz+δ=0 where α,β∈C&Y,δ∈R

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