Figure shows cross-sectional view of a long solid cylinder of radius 'R'. Current ' 'I' flows along outward direction along length of cylinder. Then, find \int \overrightarrow{B} \cdot \overrightarrow{d ℓ} along {BA} Given: O B=(\sqrt{3}+1) R, O A=2 R, \angle O B A=45^{\circ} . Where 'O' is point of axis of cylinder.

JEE Advanced 2020 Full Test 1 Paper 1

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Figure shows cross-sectional view of a long solid cylinder of radius 'R'. Current ' 'I' flows along outward direction along length of cylinder. Then, find ∫

→

⋅

→

dℓ

along BA
Given: OB=(√3+1)R,OA=2R,∠OBA=45∘. Where 'O' is point of axis of cylinder.

µ0‌
I
6
−µ0‌
I
6
‌
µ0I√7
6
‌
−µ0I
12

Validate

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