JEE Advanced 2020 Concept Recapitulation Test 4 Paper 2

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Question : 49 of 54
 
Marks: +1, -0
The value of
lim
t→0
‌ln
(‌
1
t
‌
1
∫
0
(1+2‌sin‌3‌x)4∕xdx
)
is equal to:
  • Your Answer:
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