The solubility product of {Co}_{2}[ {Fe}( {CN})_{6}] in water is {K} \times 10^{-16}. The value of {K} is Given \lambda_{ {m}}^{*} {Co}^{+2}=80 Ω^{-1} {cm}^{-1} {mol}^{-1} \lambda_{m}^{*}[ {Fe}( {CN})_{6}]^{-4}=40 Ω^{-1} {cm}^{-1} {mol}^{-1} Specific conductivity of saturated solution =2 \times 10^{-6} Ω^{-1} {c} {m}^{-1} Specific conductivity of water used ==4 \times 10^{-7} Ω^{-1} {c} {m}^{-1}

JEE Advanced 2020 Concept Recapitulation Test 4 Paper 1

Question : 35 of 54

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The solubility product of Co2[Fe(CN)6] in water is K×10−16. The value of K is Given λm*Co+2=80Ω−1cm−1mol−1 λm*[Fe(CN)6]−4=40Ω−1cm−1mol−1 Specific conductivity of saturated solution =2×10−6Ω−1cm−1 Specific conductivity of water used ==4×10−7Ω−1cm−1

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