Two identical disc A and B of equal mass ' m ' and radius 'R' are connected by a massless rod. The centres of disc C of mass ' {m}^{'} and radius 4 {R} and disc {B} are connected by massless rod which makes an angle of 30^{\circ} with the horizontal. There is no slipping between each disc and surface on which it rolls. When angular speed of disc {C} is \omega_{0}, rod connecting disc {A} and {B} makes an angle 60^{\circ} with horizontal. Then, at the given instant

Angular speed of disc A is 4 \omega_{0} \/ \sqrt{3}

Angular speed of disc A is 2 \omega_{0} \/ \sqrt{3}

The total kinetic energy of the system is 28 {m} \omega_{0}^{2} R^{2}

The total kinetic energy of the system is 26 {m} \omega_{0}^{2} {R}^{2}

JEE Advanced 2020 Concept Recapitulation Test 3 Paper 2

Question : 14 of 54

Marks: +1, -0

Two identical disc A and B of equal mass ' m ' and radius 'R' are connected by a massless rod. The centres of disc C of mass ' m′ and radius 4R and disc B are connected by massless rod which makes an angle of 30∘ with the horizontal. There is no slipping between each disc and surface on which it rolls. When angular speed of disc C is ω0, rod connecting disc A and B makes an angle 60∘ with horizontal. Then, at the given instant

Angular speed of disc A is 4ω0∕√3
Angular speed of disc A is 2ω0∕√3
The total kinetic energy of the system is 28mω02R2
The total kinetic energy of the system is 26mω02R2

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