JEE Advanced 2020 Concept Recapitulation Test 3 Paper 1
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Question : 52 of 54
Marks:
+1,
-0
The graph of x 2 + y 2 + 6 x − 24 y + 72 = 0 x 2 − y 2 + 6 x + 16 y − 46 = 0
Sum of the distance of these four points from the point( − 3 , 2 ) α
=
Sum of the distance of these four points from the point
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