If (1+a x+b x^{2})^{4}=a_{0}+a_{1} x+a_{2} x^{2}+. . . . . . . .+a_{8} x^{8} where a, b, a_{0}, a_{1}, a_{2} . . . . a_{8} \in R such that a_{0}+a_{1}+a_{2} \neq 0 and |\table a_{0} , a_{1} , a_{2} ; a_{1} , a_{1} , a_{0} ; a_{2} , a_{0} , a_{1}|=0 then

JEE Advanced 2020 Concept Recapitulation Test 3 Paper 1

Question : 42 of 54

Marks: +1, -0

If (1+ax+bx2)4=a0+a1x+a2x2+........+a8x8 where a,b,a0,a1,a2....a8∈R such that a0+a1+a2≠0 and |

|=0 then

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