JEE Advanced 2020 Concept Recapitulation Test 1 Paper 2

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Question : 44 of 54

Marks: +1, -0

For k∈N, let bk=

e

∫

1

‌

1

(k+log‌x)(k+1+log‌x)

‌

dx

x

and an=

∑

k=1

nbk. Then

bk=log(‌
(k+1)2
k(k+2)
)
an=log(‌
2n+2
n+2
)
lim
n→∞
an=log‌2
lim
n→∞
an<1

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