JEE Advanced 2020 Concept Recapitulation Test 1 Paper 1

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Question : 51 of 54

Marks: +1, -0

Let 0≤βr≤1 and

k

∑

r=1

cos−1βr=‌

kπ

2

for any k≥1 and A=

k

∑

r=1

(βr)r, then

lim

x→A

498⋅‌

(1+x2)1∕3−(1−2x)1∕4

x+x2

is equal to λ, where ‌

λ

83

=

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