JEE Advanced 2019 Paper 2

Answer the following by appropriately matching the lists based on the information given in the paragraph.
In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX , where T is temperature of the system and ΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monatomic ideal gas X=

3

2

Rln(

T

TA

)+Rln(

V

VA

).Here R is gas constant, V is volume of gas TA and VA are constants The List-I below gives some quantities involved in a process and List-II gives some possible values of these quantities.

List I	List II
I) Work done by the system in process 1→2→3	P) ‌‌ 1 3 RT0‌ln‌2
II) Change in internal energy in process 1→2→3	Q) ‌‌ 1 3 RT0
III) Heat absorbed by the system in process 1→2→3	R) RT0
IV) Heat absorbed by the system in process 1→2	S) 4 3 RT0
	T) ‌‌ 1 3 RT0(3+ln‌2)
	U) ‌‌ 5 6 RT0

If the process on one mole of monatomic ideal gas is as shown in the TV-diagram with P0V0=

1

3

RT0,the correct match is,

	I	II	III	IV
1)	P	R	T	S
2)	P	T	Q	T
3)	S	T	Q	U
4)	P	R	T	P