For an isosceles prism of angle A and refractive index \mu, it is found that the angle of minimum deviation \delta_m=A which of the following is/are correct [JEE Adv 2017 P1]

At minimum deviation, the incident angle i_1 and the refracting angle r_1 at the first refracting surface are realted by r_1=(i_1/2)

For this prism, the refractive index μ and the angle of prism A are related as A=1/2cos^{-1}(\mu/2)

For the angle of incidence i_1=A,the ray inside the prism is parallel to the base of the prism

For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is i_1= \sin^{-1}A\sqrt{4cos^2A/2-1-cosA}

JEE Advanced 2017 Paper 1

Section: Physics

Question : 6 of 54

Marks: +1, -0

For an isosceles prism of angle A and refractive index µ, it is found that the angle of minimum deviation δm=A which of the following is/are correct

[JEE Adv 2017 P1]

At minimum deviation, the incident angle i1 and the refracting angle r1 at the first refracting surface are realted by r1=(
i1
2
)
For this prism, the refractive index μ and the angle of prism A are related as A=
1
2
cos−1(
µ
2
)
For the angle of incidence i1=A,the ray inside the prism is parallel to the base of the prism
For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is i1= sin−1A√4cos2
A
2
−1−cosA

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