For two structure namely S_1\text{with}n_1=\sqrt45/4 and n_2=3/2, and S_2\text{with} n_1=8/5 and n_2=7/5 and taking refractive index of water to be 4.3 and that of air to be 1,the correct option(s) is (are) [JEE Adv 2015 P2]

NA of S_1 immersed in water is the same as that of S_2 immersed in a liquid of refractive index 16/{3\sqrt15}

NA of S_1 immersed in liquid of refaractive index 6/\sqrt15 is the same as that of S_2 immersed in water

NA of S_1 placed is the same as that of S_2 immersed in liquid of refractiv index 4/\sqrt15

NA of S_1 placed in air is the same as that of S_2 placed in water

JEE Advanced 2015 Paper 2

Paragraph for next 2 Questions
Light guidance in an optical fiber can be understood by considering a structure comprising of thin solid glasscylinder of refractive index n1 surrounded by a medium of lower refractive index n2. The light guidance in thestructure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown inthe figure. All rays with the angle of incidence i less than a particular value im are confined in the medium ofrefractive index n1. The numerical aperture (NA) of the structure is defined as sin im.

Section: Physics

Question : 17 of 60

Marks: +1, -0

For two structure namely S1‌with‌n1=

√45

‌ and ‌n2=

, and ‌S2withn1=

and n2=

and taking refractive index of water to be 4.3 and that of air to be 1,the correct option(s) is (are)

[JEE Adv 2015 P2]

NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive index
16
3√15
NA of S1 immersed in liquid of refaractive index
6
√15
is the same as that of S2 immersed in water
NA of S1 placed is the same as that of S2 immersed in liquid of refractiv index
4
√15
NA of S1 placed in air is the same as that of S2 placed in water

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