A young's double slit interference arrangement with slit S_1 \text{and} S_2 is immersed in water (refractive index=4/3) as shown in the figure.The position of maxima on the surface of water are given by x^2=p^2m^2\lambda^2-d^2,where \lambda is the wave length of light in air (refractive index =1),2d is the separation between the slits and m is an integer.The value of p is ? [JEE Adv 2015 P1]

JEE Advanced 2015 Paper 1

Section: Physics

Question : 8 of 60

Marks: +1, -0

A young's double slit interference arrangement with slit S1andS2 is immersed in water (refractive index=4/3) as shown in the figure.The position of maxima on the surface of water are given by x2=p2m2λ2−d2,where λ is the wave length of light in air (refractive index =1),2d is the separation between the slits and m is an integer.The value of p is ?

[JEE Adv 2015 P1]

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