Let E_1(r),E_2(r) and E_3(r) be the respective electric fields at a distance r from a point charge Q ,an infinitely long wire with constant linear charge density \lambda ,and an infinite plane with uniform surface charge density \sigma.If E_1(r_0)=E_2(r_0)=E_3(r_0) at a given distance r_0,then [JEE Adv 2014 P1]

Correct Answer is : E1(r02)=2E2(r02)

JEE Advanced 2014 Paper 1

Section: Physics

Question : 8 of 60

Marks: +1, -0

Let E1(r),E2(r) and E3(r) be the respective electric fields at a distance r from a point charge Q ,an infinitely long wire with constant linear charge density λ ,and an infinite plane with uniform surface charge density σ.If E1(r0)=E2(r0)=E3(r0) at a given distance r0,then

[JEE Adv 2014 P1]

Q=4σπr02
r0=
λ
2πσ
E1(
r0
2
)=2E2(
r0
2
)
E2(
r0
2
)=4E3(
r0
2
)

Validate

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