JEE Advanced 2013 Paper 2

Section: Physics
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Question : 5 of 60
 
Marks: +1, -0
Using the expression 2d sin θ = λ, one calculates the values of d by measuring the corresponding angles θ in the range 0 to 900. The wavelength λ is exactly known and the error in θ is constant for all values of θ. As θ increases from 00 :
[JEE Adv 2013 P2]
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