Evaluate \int(x+\frac{1}{x})^{2} d x

Correct Answer is : x33+2x−1x+c

\frac{x^{3}}{3}+2 x-\frac{1}{x}+c

Integral Calculus

Question : 43 of 73

Marks: +1, -0

Evaluate

∫(x+\;{1}/{x})^{2} d x

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