Evaluate \int \log (x+1) d x

Correct Answer is : xlog(x+1)−x+log(x+1)+c

x^{2} \log (x+1)-x^{2}+\log (x^{2}+1)+c

x \log (x+1)-x^{2}+\log (x+1)+c

Integral Calculus

Question : 36 of 73

Marks: +1, -0

Evaluate

∫ \log (x+1) d x

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