Evaluate \int 2^{x} x^{2} d x

Correct Answer is : 2xx2log2−x2x+1(log2)2+2x+1(log2)3+c

{2^{x} x^{2}}/{\log 2}- {x 2^{x+1}}/{(\log 2)^{2}}+ {2^{x+1}}/{(\log 2)^{3}}+c

{2^{x} x^{3}}/{3}- {x^{2} 2^{x+1}}/{(\log 2)^{2}}+ {2^{x+1}}/{(\log 3)^{2}}+c

{2^{x} \cdot x^{2}}/{3}- {x^{3} \cdot 2^{x}}/{3}- {2^{x+1}}/{(\log 2)^{3}}+c

Integral Calculus

Question : 31 of 73

Marks: +1, -0

Evaluate

∫ 2^{x} x^{2} d x

$\;{2^{x} x^{2}}/{\log 2}-\;{x 2^{x+1}}/{(\log 2)^{2}}+\;{2^{x+1}}/{(\log 2)^{3}}+c$
$\;{2^{x} x^{3}}/{3}-\;{x^{2} 2^{x+1}}/{(\log 2)^{2}}+\;{2^{x+1}}/{(\log 3)^{2}}+c$
$\;{2^{x} ⋅ x^{2}}/{3}-\;{x^{3} ⋅ 2^{x}}/{3}-\;{2^{x+1}}/{(\log 2)^{3}}+c$
None

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