If \frac{x}{b+c-a}=\frac{y}{c+a-b}=\frac{z}{a+b-c}, then find the value of (b-c) x+(c-a) y+(a-b) z= b+c-a c+a-b a+b-c

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Question : 86 of 86

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If

\;{x}/{b+c-a}=\;{y}/{c+a-b}=\;{z}/{a+b-c},

then find the value of

(b-c) x+(c-a) y+(a-b) z=

b+c-a c+a-b a+b-c

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