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Question : 41 of 86

Marks: +1, -0

On simplification

\;{1}/{1+z^{a-b}+z^{a-c}}+\;{1}/{1+z^{b-c}+z^{b-a}}+\;{1}/{1+z^{c-a}+z^{c-b}}

reduces to:

$\;{1}/{z(a+b+c)}$
$\;{1}/{z^{(a+b+c)}}$
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