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Question : 27 of 86

Marks: +1, -0

If

2^{x}=4^{y}=8^{z}

and

(\;{1}/{2 x}+\;{1}/{4 y}+\;{1}/{6 z})=\;{24}/{7}

, then the value of

z

is:

$\;{7}/{16}$
$\;{7}/{32}$
$\;{7}/{48}$
$\;{7}/{64}$

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