Indian Institute of Foreign Trade 2016 Solved Paper

(b) The two sides of the square are
6x – 8y = 15 and 4y – 3x = 2
or 6x – 8y = 15 $$(1)
and 6x – 8y = – 4 $$ (2)
These two lines are parallel each other. So the distance between the two parallel lines would be the side of the square.
∴ side of square$=\frac{\left|15-\left(-4\right)\right|}{\sqrt{6^2+8^2}}=\frac{19}{10}$
∴ Area of square $={\left(\frac{19}{10}\right)}^2=\frac{361}{100}=3.61$ sq. units