Indian Institute of Foreign Trade 2015 Solved Paper

Question : 12 of 124

Marks: +1, -0

If in the figure below, angle XYZ = 90° and the length of the arc XZ = 10 π, then the area of the sector XYZ is:

Solution:

π

{ θ }/ { 360 } × 2 π r = 10 π

{ 90 } /{ 360 } ×2 π r = 10 π

r = 20 π\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;...(1)

Now, Area of sector

= { θ}/ { 360 } × π r ^ { 2 }

= { 90 }/ { 360 } × π× 400 = 100 π

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