Indian Institute of Foreign Trade 2012 Solved Paper

The volume of the hot water in the hemispherical bowl $=\frac{2\times \mathit{\pi }\times {\mathit{r}}^3}{3}$
Given that Radius of the hemispherical bowl and that of the cylindrical vessel is the same.
Also, radius is 50% more than its height
Thus, $\mathit{h}=\frac{2\mathit{r}}{3}$
Thus, the volume of the cylindrical vessel $=\frac{2\times \mathit{\pi }\times {\mathit{r}}^3}{3}$
Hence, the volume of the hot water in the cylindrical vessel is 100% of the cylindrical vessel.
Hence, option C is the correct answer