Indian Institute of Foreign Trade 2011 Solved Paper

The ratio of ‘metal 1’ and ‘metal 2’ in alloy ‘A’ is 3 :4.Therefore, we can say that 14 kg of alloy 'A' will contain $\frac{3}{714}=6$
kg of 'metal 1' and $\frac{4}{714}=8$ kg of 'metal 2'.
The ratio of ‘metal 1’ and ‘metal 2’ in alloy ‘B’ is 5 :8.Therefore, we can say that 26 kg of alloy 'B' will contain $\frac{5}{1326}=10$kg of 'metal 1' and $\frac{8}{1326}=16$ kg of metal 2'
Hence, total weight of 'metal 1' in the new alloy $=6+10=16\mathit{k}\mathit{g}$
Total weight of 'metal 2' in the new alloy $=8+16=24$kg
Therefore, the ratio of ‘metal 1’ and ‘metal 2’ in the new alloy. $=16:24=2:3$. Hence, option C is the correct answer.