Indian Institute of Foreign Trade 2009 Solved Paper

which is always < 0.2 but a positive number.
Option A=${\mathit{e}}^2-1=7.34-1=6.34$ therefore this cannot be the Answer
Option B$={\log }_{\mathit{e}}2-1=\frac{{\log }_{10}2}{{\log }_{10}\mathit{e}}-1=\frac{{\log }_{10}2}{{\log }_{10}2.72-1}$
We know that the value of $\frac{{\log }_{10}2}{{\log }_{10}2.72-1}$ < 1 1 and therefore value of
therefore this cannot be the Answer
Option C $=2{\log }_{10}2-1={\log }_{10}4-1$
We know that the value of and therefore value of
therefore this cannot be the Answer
Therefore the Answer is option 'D'