Indian Institute of Foreign Trade 2008 Solved Paper

The cylinder, hemisphere and cone stand on the same base and have the same height. Let the radius of the threesolids be and the height be h.
Height of the hemisphere h = r(radius)
Curved surface area of the cylinder $=2\ast \mathit{\pi }\ast \mathit{r}\ast \mathit{r}=2\ast \mathit{\pi }\ast {\mathit{r}}^2$
Curved surface area of the hemisphere $=2\ast \mathit{\pi }\ast {\mathit{r}}^2$
Curved surface area of the cone Ratio $=2:2:\sqrt{2}=\sqrt{2}:\sqrt{2}:1$
As the answer is not among the given options, option D is the right answer