The integral \int {\sec^2 x}/(secx+tanx)^{9/2} dx equals (for some arbitraryconstant K) [JEE Adv 2012 P1]

Correct Answer is : −1(secx+tanx)112{111+17(secx+tanx)2}+K

- 1/(secx+tanx)^{{11}/2} \{1/{11}-1/7(secx+tanx)^2\} + K

-1/(secx+tanx)^{{11}/2} \{1/{11}-1/7(secx+tanx)^2\} + K

- 1/(secx+tanx)^{{11}/2} \{1/{11}+1/7(secx+tanx)^2\} + K

1/(secx+tanx)^{{11}/2} \{1/{11}+1/7(secx+tanx)^2\} + K

IIT JEE Advanced 2012 Paper 1

Section: Mathematics

Question : 45 of 60

Marks: +1, -0

The integral ∫

sec2x

(secx+tanx)

dx equals (for some arbitraryconstant K)

[JEE Adv 2012 P1]

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