IIT JEE Advanced 2011 Paper 2

Section: Physics

Question : 20 of 60

Marks: +1, -0

Column I shows four systems, each of the same length L, for producing standing waves. The lowest possible natural frequency of a system is called its fundamental frequency, whose wavelength is denoted as λf. Match each system with statements given in Column II describing the nature and wavelength of the standing waves:

Column I	Column II
(A) Pipe closed at one end	(P) Longitudinal waves
(B) Pipe open at both ends	(Q) Transverse waves
(C) Stretched wire clamped at both sides	(R) λf = L
(D) Stretched wire clamped at both ends and at mid-point	(S) λf = 2L
	(T) λf = 4L

[JEE Adv 2011 P2]

(A)→(P), (T); (B)→(P), (S); (C)→(Q), (S); (D)→(Q), (R)
(A)→(P), (R); (B)→(P), (S); (C)→(Q), (S); (D)→(Q), (S)
(A)→(P), (S); (B)→(P), (S); (C)→(Q), (S); (D)→(P), (R)
(A)→(P), (T); (B)→(P), (S); (C)→(R), (S); (D)→(Q), (S)

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