IIT JEE Advanced 2009 Paper 2

Section: Mathematics

Question : 46 of 57

Marks: +1, -0

An ellipse intersects the hyperbola 2x2–2y2 = 1 orthogonally. The eccentricity of the ellipse is reciprocal of that of the hyperbola. If the axes of the ellipse are along the coordinates axes, then

[JEE Adv 2009 P2]

equation of ellipse is x2+2y2 = 2.
the foci of ellipse are (± 1, 0).
equation of ellipse is x2+2y2 = 4.
the foci of ellipse are (±√2,0).

Validate

Go to Question:

Prev Question

Next Question