IIT JEE Advanced 2009 Paper 2

Section: Physics
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Question : 16 of 57
 
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A 20 cm long string, having a mass of 1.0 g, is fixed at both the ends. The tension in the string is 0.5 N. The string is set into vibrations using an external vibrator of frequency 100 Hz. Find the separation (in cm) between the successive nodes on the string.
[JEE Adv 2009 P2]
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