A block of base 10 cm×10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is \sqrt3. The inclination θ of this inclined plane from the horizontal plane is gradually increased from 0°. Then [JEE Adv 2009 P1]

Correct Answer is : the block will remain at rest on the plane up to certain θ and then it will topple.

at θ = 30°, the block will start sliding down the plane.

the block will remain at rest on the plane up to certain θ and then it will topple.

at θ = 60°, the block will start sliding down the plane and continue to do so at higher angles.

at θ = 60°, the block will start sliding down the plane and on further increasing θ , it will topple at certain θ.

IIT JEE Advanced 2009 Paper 1

Section: Physics

Question : 8 of 60

Marks: +1, -0

A block of base 10 cm×10 cm and height 15 cm is kept on an inclined plane. The coefficient of friction between them is √3. The inclination θ of this inclined plane from the horizontal plane is gradually increased from 0°. Then

[JEE Adv 2009 P1]

at θ = 30°, the block will start sliding down the plane.
the block will remain at rest on the plane up to certain θ and then it will topple.
at θ = 60°, the block will start sliding down the plane and continue to do so at higher angles.
at θ = 60°, the block will start sliding down the plane and on further increasing θ , it will topple at certain θ.

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