IIT JEE Advanced 2009 Paper 1

Section: Chemistry

Question : 24 of 60

Marks: +1, -0

The Henry’s law constant for the solubility of N2 gas in water at 298 K is 1.0 × 105 atm. The mole fraction of N2 in air is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298 K and 5 atm pressure is

[JEE Adv 2009 P1]

4.0 × 10−4
4.0 × 10−5
5.0 × 10−4
4.0 × 10−6

Validate

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