IIT JEE Advanced 2008 Paper 2

Section: Chemistry

Question : 24 of 66

Marks: +1, -0

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 mA current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 faraday constant = 96,500 C mol−1)

[JEE Adv 2008 P2]

9.65 × 104 s
19.3 × 104 s
28.95 × 104 s
38.6 × 104 s

Validate

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