IIT JEE Advanced 2008 Paper 1

Section: Mathematics

© examsiri.com

Question : 49 of 69

Marks: +1, -0

Let g (x) =

(x−1)n

log‌cosm(x−1)

; 0 < x < 2 , m and n are integers, m ≠ 0, n > 0, and let p be the left hand derivative of |x – 3| at x = 1. If

lim

x→1+

g (x) = p , then

[JEE Adv 2008 P1]

n = 1, m = 1
n = 1, m = –1
n = 2, m = 2
n > 2, m = n

Go to Question:

Prev Question

Next Question