Let f (x) = x/(1+x)^{1/n} for n ≥ 2 and g (x) = (fofo...of)_{\f \occurs \n \times} (x). Then \int x^{n-1} g (x) dx equals [JEE Adv 2007 P2]

Correct Answer is : 1n(n−1)(1−nxn)1−1n + K

1/{n(n-1)} (1-nx^n)^{1-1/n} + K

1/{n(n-1)} (1+nx^n)^{1-1/n} + K

1/{n(n+1)} (1+nx^n)^{1+1/n} + K

IIT JEE Advanced 2007 Paper 2

Section: Mathematics

Question : 52 of 66

Marks: +1, -0

Let f (x) =

(1+x)

for n ≥ 2 and g (x) =

(fofo...of)

f‌occurs‌n‌times

(x).
Then ∫xn−1g(x) dx equals

[JEE Adv 2007 P2]

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