Let a^{\to},b^{\to},c^{\to} be unit vectors such that a^{\to}+b^{\to}+c^{\to} = 0^{\to}. Which one of the following is correct? [JEE Adv 2007 P2]

Correct Answer is : →a×→b = →b×→c = →c×→a ≠ →0.

a^{\to}\timesb^{\to} = b^{\to}\timesc^{\to} = c^{\to}\timesa^{\to} = 0^{\to}.

a^{\to}\timesb^{\to} = b^{\to}\timesc^{\to} = c^{\to}\timesa^{\to} ≠ 0^{\to}.

a^{\to}\timesb^{\to} = b^{\to}\timesc^{\to} = a^{\to}\timesc^{\to} ≠ 0^{\to}.

a^{\to}\timesb^{\to} , b^{\to}\timesc^{\to} , c^{\to}\timesa^{\to} are mutually perpendicular.

IIT JEE Advanced 2007 Paper 2

Section: Mathematics

Question : 50 of 66

Marks: +1, -0

Let

→

be unit vectors such that

→

. Which one of the following is correct?

[JEE Adv 2007 P2]

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