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IIT JEE Advanced 2006 Paper 1

Section: Chemistry
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Question : 79 of 120
 
Marks: +1, -0
According to Bohr’s theory, En = Total energy, Kn = Kinetic energy, Vn = Potential energy, Rn = Radius of nth orbit. Match Column I with Column II:
Column I Column II
(A)
Vn
Kn
 = ?		(P) 0
(B) If radius of nth orbit ∝ Enx , x = ? (Q) - 1
(C) Angular momentum in lowest orbital (R) - 2
(D)
1
rn
 α Zy , y = ? 		(S) 1

[JEE Adv 2006 P1]
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