IIT JEE Advanced 2006 Paper 1
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Question : 114 of 120
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If f(x) is twice differentiable function such that f(a) = 0, f(b) = 2, f(c) = 1, f(d) = 2, f(e) = 0, where a < b < c < d < e, then the minimum number of solution(s) of g(x) = { f (x)}2 + f ′′(x) ⋅ f (x) in the interval [a, e] is ____.
[JEE Adv 2006 P1]
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