IBPS SO Prelims Exam Model Paper 9

Calculations:I. 4 x2 – 9x + 2 = 0
⇒ 4x2 – 8x – x + 2 = 0
⇒ 4x(x – 2) – 1(x – 2) = 0
⇒ (4x – 1)(x – 2) = 0
⇒ x =

1

4

and x = 2
II. 3 y2 + 7y + 2 = 0
⇒ 3y2 + 6y + y + 2 = 0
⇒ 3y(y + 2) + 1(y + 2) = 0
⇒ (3y + 1) (y + 2) = 0
⇒ y = −

1

3

and y = -2∴ x > y