IBPS SO Prelims Exam Model Paper 8

Given:
Side of a cube = 6 cm
Formula used:
Volume of a cube = (side)3
Volume of a cone = (

1

3

) × π × r2 × h
Calculation:
Maximum cone which can formed by cube
Height of cone = 6 cm
Radius of cone = 3 cm
Volume of cone = (

1

3

) × π × (3)2 × 6
⇒ 18π
Volume of a cube = (6)3
⇒ 216
Waste part of a cube = Volume of a cube – Volume of a cone
⇒ 216 - 18π
Ratio of waste part to the cone = [

(216−18π)

18π

]
⇒

[216–(18× 22 7 )]

(18× 22 7 )

⇒

[ (1512–396) 7 ]

(18× 22 7 )

⇒ [

( 1116 7 )

( 396 7 )

]
⇒

31

11

⇒ 31 : 11