IBPS SO Prelims Exam Model Paper 6

I. 11x2 – 43x – 4 = 0
⇒ 11x2 + x – 44x – 4 = 0
⇒ (11x + 1) (x – 4) = 0
⇒ x = −

1

11

, 4
II. 44y2 + 125y + 11 = 0
⇒ 44y2 + 121y + 4y + 11 = 0
⇒ (4y + 11) (11y + 1) = 0
⇒ y = −

11

4

, −

1

11

Hence, x ≥ y