IBPS SO Prelims Exam Model Paper 3

I. 3x2 – 4x – 32 = 0
⇒ 3x2 – 12x + 8x – 32 = 0
⇒ 3x(x – 4) + 8(x – 4) = 0
⇒ (x – 4) (3x + 8) = 0
∴ x = 4 or −

8

3

II. 2y2 + 5y – 3 = 0
⇒ 2y2 + 6y – y – 3 = 0
⇒ 2y(y + 3) – 1(y + 3) = 0
⇒ (y + 3) (2y – 1) = 0
∴ y = -3 or

1

2

⇒ So, when x = 4, for y = - 3 or

1

2

⇒ And when x = −

8

3

, for y = - 3 or

1

2

∴ We can observe that no relationship could be established