IBPS SO Prelims Exam Model Paper 2

For eq 1:
x2 – 11x + 24 = 0
⇒ x2 – 3x – 8x + 24 = 0
⇒ x(x – 3) – 8(x – 3) = 0
⇒ (x – 3)(x – 8) = 0
⇒ x = 3, 8
For eq 2:
y2 – 9y + 14 = 0
⇒ y2 – 2y – 7y + 14 = 0
⇒ y(y – 2) – 7(y – 2) = 0
⇒ (y – 2)(y – 7) = 0
⇒ y = 2, 7
When x = 3, y = 2, then x > y
When x = 3, y = 7, then x < y
When x = 8, y = 2, then x > y
When x = 8, y = 7, then x > y
∴ No relation is obtained between x and y