IBPS SO Prelims Exam Model Paper 2

I. x2 – 11x + 28 = 0
⇒ x2 – 7x - 4x + 28 = 0
⇒ x(x – 7) - 4(x – 7) = 0
⇒ (x – 4) (x - 7) = 0
∴ x = 4, 7
II. y2 + 8y – 48 = 0
⇒y2 + 12y – 4y – 48 = 0
⇒ y(y + 12) - 4(y + 12) = 0
⇒ (y - 4) (y + 12) = 0
∴ y = 4, -12
For x = 4 and y = 4, y = x and for x = 4 and y = -12, x > y
For x = 7 and y = 4, x > y and for x = 7 and y = -12, x > y
∴ x ≥ y