IBPS SO Prelims Exam Model Paper 10

Statement II:
When (N3 – N) is divided by 6, remainder is 0.
(N3–N) = N(N2–1) = N(N – 1)(N + 1)
It is the product of 3 consecutive numbers.
We already know that the product of 3 consecutive numbers is always completely divisible by 6.
Hence, nothing can be concluded from statement II alone.
Statement I:
When the number N is divided by 18, reminder is 8.
So, we can write:
N = 18a + 8
⇒ N = 6 × (3a + 1) + 2
When the number is divided by 6, the remainder will be 2 only.
∴ Statement I alone is sufficient to answer the question.